Reputation: 855
I am having some trouble wrapping my head around how to traverse a certain graph to extract some data.
Given a collection of "users" and a collection of "places".
And a "likes" edge collection to denote that a user likes a certain place. The "likes" edge collection also has a "review" property to store a user's review about the place.
And a "follows" edge collection to denote that a user follows another user.
How can I traverse the graph to fetch all the places that I like with my review of the place and the reviews of the users I follow that also like the same place.
for example, in the above graph. I am user 6327 and I reviewed both places(7968 and 16213) I also follow user 6344 which also happens to have reviewed the place 7968.
How can I get all the places that I like and the reviews of the people that I follow who also reviewed the same place that I like.
an expected output would be something like the following:
[
{
name:"my name",
place: "place 1",
id: 1
review,"my review about place 1"
},
{
name:"my name",
place: "place 2",
id: 2
review,"my review about place 2"
},
{
name:"name of the user I follow",
place: "place 2",
id: 2
review,"review about place 2 from the user I follow"
}
]
Upvotes: 2
Views: 3211
Reputation: 2349
There are a number of ways to do this query, and it also depends on where you want to add parameters, but for the sake of simplicity I've built this quite verbose query below to help you understand one way of approaching the problem.
One way is to determine the _id
of your user record, then find all the _id
's of the friends you follow, and then to work out all related reviews in one query.
I take a different approach below, and that is to:
It is possible to merge these queries together more optimally, but I thought it worth breaking them out like this (and showing the output of each stage as well as the final answer) to help you see what data is available.
A key thing to understand about AQL graph queries is how you have access to vertices, edges, and paths when you perform a query.
A path is an object in it's own right and it's worth investigating the contents of that object to better understand how to exploit it for path information.
This query assumes:
users
document collection contains usersplaces
document collection contains placesfollows
edge collection tracks users following other usersreviews
edge collection tracks reviews people wroteNote: When providing an id
on each record I used the id
of the review
, because if you know that id you can fetch the edge document and get the id
of both the user
and the place
as well as read all the data about the review
.
LET my_reviews = (
FOR vertices, edges, paths IN 1..1 OUTBOUND "users/6327" reviews
RETURN {
name: FIRST(paths.vertices).name,
review_id: FIRST(paths.edges)._id,
review: FIRST(paths.edges).review,
place: LAST(paths.vertices).place
}
)
LET who_i_follow = (
FOR v IN 1..1 OUTBOUND "users/6327" follows
RETURN v
)
LET reviews_of_who_i_follow = (
FOR users IN who_i_follow
FOR vertices, edges, paths in 1..1 OUTBOUND users._id reviews
RETURN {
name: FIRST(paths.vertices).name,
review_id: FIRST(paths.edges)._id,
review: FIRST(paths.edges).review,
place: LAST(paths.vertices).place
}
)
RETURN {
my_reviews: my_reviews,
who_i_follow: who_i_follow,
reviews_of_who_i_follow: reviews_of_who_i_follow,
merged_reviews: UNION(my_reviews, reviews_of_who_i_follow)
}
The first vertex in paths.vertices
is the starting vertex (users/6327
)
The last vertex in paths.vertices
is the end of the path, e.g. who you follow
The first edge in paths.edges
is the review that the user
made of the place
Here is another more compact version of the query that takes a param, the _id of the user that is 'you'.
LET target_users = APPEND(TO_ARRAY(@user), (
FOR v IN 1..1 OUTBOUND @user follows RETURN v._id
))
LET selected_reviews = (
FOR u IN target_users
FOR vertices, edges, paths in 1..1 OUTBOUND u reviews
LET user = FIRST(paths.vertices)
LET place = LAST(paths.vertices)
LET review = FIRST(paths.edges)
RETURN {
name: user.name,
review_id: review._id,
review: review.review,
place: place.place
}
)
RETURN selected_reviews
Upvotes: 4