CODEWITHSUNDEEP
rrandom-foresthanapmmlhana-studio
KayEd
KayEd

Reputation: 3

How to save an R randomForest object within SAP HANA Studio?

I'm pretty new in SAP World and I’m trying to work with R Server installed within SAP HANA Studio (Version of HANA Studio : 2.3.8 & Version of R Server 3.4.0)

My tasks are:

Here is a small example of RLANG procedure for training a saving the model on HANA:

    PROCEDURE "PA"."RF_TRAIN" ( 
    IN data "PA"."IRIS", 
    OUT modelOut "PA"."TRAIN_MODEL"
 ) 
    LANGUAGE RLANG 
SQL SECURITY INVOKER 
DEFAULT SCHEMA "PA"
AS
BEGIN

require(randomForest)
require(dplyr)
require(pmml)
# iris <- as.data.frame(data)
data(iris)
iris <- iris %>% mutate(y = factor(ifelse(Species == "setosa", 1, 0)))
model <- randomForest(y~Sepal.Length + Sepal.Width + Petal.Length + Petal.Width, iris,
         importance = TRUE,
         ntree = 500)
modelOut <- as.data.frame(pmml(model))

END;

(Please don’t be confused, that I’m not using my input data for model training, this is not a real example)

Here is how a table with the model on SAP HANA should look like:

model on SAP HANA

In this example training is working, but I’m not sure how to save the randomForest-Object on SAP HANA data base or how to convert the randomForest-Object into similar one in the picture.

Would appreciate any help :)

Upvotes: 0

Views: 326

Answers (1)

AshOfFire
AshOfFire

Reputation: 676

If you plan to use R server for your predictions, you can store your random Forest model as a BLOB object in SAP HANA.

Following the SAP HANA R Integration Guide, you need to.

  1. Include a BLOB attribute to your table "PA"."TRAIN_MODEL.
  2. Store the model as binary with function serialize before writing it in your table.
  3. Load and Unserialize your model when calling predict procedure.

Which would give, in your R script.

require(randomForest)
require(dplyr)
require(pmml)
generateRobjColumn <- function(...){
        result <- as.data.frame(cbind(
            lapply(
                list(...),
                function(x) if (is.null(x)) NULL else serialize(x, NULL)
            )
        ))
        names(result) <- NULL
        names(result[[1]]) <- NULL
        result
    }
# iris <- as.data.frame(data)
data(iris)
iris <- iris %>% mutate(y = factor(ifelse(Species == "setosa", 1, 0)))
model <- randomForest(y~Sepal.Length + Sepal.Width + Petal.Length + Petal.Width, iris,
         importance = TRUE,
         ntree = 500)
modelOut <- data.frame(ID = 1, MODEL = generateRobjColumn(pmml(model)))

Note that you don't actually need to use pmml if you plan to re-use the model as is.

In another procedure, you will need to call this table and unserialize your model for prediction.

CREATE PROCEDURE "PA"."RF_PREDICT" (IN data "PA"."IRIS", IN modelOut "PA"."TRAIN_MODEL", OUT result "PA"."PRED")
LANGUAGE RLANG AS
BEGIN
  rfModel <- unserialize(modelOut$MODEL[[1]])
  result <- predict(rfModel, newdata = data) # or whatever steps you need for prediction
END;

Upvotes: 0

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