CODEWITHSUNDEEP
listdictionaryansibleyamljinja2
Ossar
Ossar

Reputation: 23

Ansible / jinja2 list of dicts of lists

I am trying to compose a list from a list of dicts of lists but am failing. Trying to get a list of all peers to r1

Example data yaml:

---
conn:
- id: asd
  peers:
  - name: r1
  - name: r2
- id: dsa
  peers:
  - name: r1
  - name: r3
- id: sad
  peers:
  - name: r2
  - name: r4

The output should be [r2,r3] as r1 only has r2 and r3 as peers. How can I get this list from an ansible task?

Upvotes: 0

Views: 826

Answers (1)

Konstantin Suvorov
Konstantin Suvorov

Reputation: 68269

You may want to explore JMESPath:

---
- hosts: localhost
  gather_facts: no
  vars:
    conn:
      - id: asd
        peers:
        - name: r1
        - name: r2
      - id: dsa
        peers:
        - name: r1
        - name: r3
      - id: sad
        peers:
        - name: r2
        - name: r4
  tasks:
    - debug:
        msg: "{{ conn | json_query(qry) }}"
      vars:
        qry: '[*].{p:peers[].name} | [?contains(p,`r1`)].p[] | [?@!=`r1`]'

Select peers[].name as p, select only items which have r1 as element of p, then flatten list and drop any r1 items effectively leaving only r1 peers as the result.

Upvotes: 1

Related Questions