Reputation: 655
I want to create an object of type Partial
, where the keys will be some combination of 'a', 'b', or 'c'. It will not have all 3 keys (edit: but it will at least have one). How do I enforce this in Typescript? Here's more details:
// I have this:
type Keys = 'a' | 'b' | 'c'
// What i want to compile:
let partial: Partial = {'a': true}
let anotherPartial: Partial = {'b': true, 'c': false}
// This requires every key:
type Partial = {
[key in Keys]: boolean;
}
// This throws Typescript errors, says keys must be strings:
interface Partial = {
[key: Keys]: boolean;
}
The two methods I've tried above (using mapped types and interfaces) don't achieve what I want. Can anyone help here?
Upvotes: 42
Views: 34488
Reputation: 191
Another way to do this is...
// I have these keys
type Keys = 'a' | 'b' | 'c'
// This type requires every key:
type WithAllKeys = {
[key in Keys]: boolean;
}
// This will have a Partial key
interface WithPartialKeys: Partial<WithAllKeys>;
Upvotes: 4
Reputation: 18271
You can use the ?
to make the keys optional, so
interface Partial {
a?: boolean;
b?: boolean;
c?: boolean;
}
Or, you can do this:
type Keys = "a" | "b" | "c";
type Test = {
[K in Keys]?: boolean
}
Upvotes: 66