CODEWITHSUNDEEP
c++functionscopecuda
Phil
Phil

Reputation: 1110

CUDA function call-able by either the device or host

I have a re-useable function in some CUDA code that needs to be called from both the device and the host. Is there an appropriate qualifier for this?

e.g. what's the correct definition for func1 in this case:

int func1 (int a, int b) {
    return a+b;
}

__global__ devicecode (float *A) {
    int i = blockDim.x * blockIdx.x + threadIdx.x;
    A[i] = func1(i,i);
}

void main() {
    // Normal cuda memory set-up

    // Call func1 from inside main:
    int j = func1(2,4)

    // Normal cuda memory copy / program run / retrieve data
}

So far I can only get this to work by having the function twice: once explicitly for the device and once for the host. Is there a better way?

Upvotes: 9

Views: 4285

Answers (1)

tkerwin
tkerwin

Reputation: 9769

From the CUDA Programming Guide:

The __device__ and __host__ qualifiers can be used together however, in which case the function is compiled for both the host and the device.

Upvotes: 18

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