CODEWITHSUNDEEP
phpregex
Tobi
Tobi

Reputation: 55

PHP Regex - Get text after some text in brackets

I'm new to regular expressions and try to extract text in a string which starts with a value in brackets on the beginning of a new line until the next string in brackets.

My string:

   (1x) cat
   dog
   (2) ele(4)phant
   tiger
   (x) fish 
   bird

I need to get: 

- "1x" and "cat\r\ndog"
- "2" and  "ele(4)phant\r\ntiger"
- "x" and "fish\r\nbird"

My regex:

(\r\n)*(\((.*?)\))(.*)

This gets me:

Match 1
Full match  0-8 `(1x) cat`
Group 2.    0-4 `(1x)`
Group 3.    1-3 `1x`
Group 4.    4-8 ` cat`

Match 2
Full match  13-28   `(2) ele(4)phant`
Group 2.    13-16   `(2)`
Group 3.    14-15   `2`
Group 4.    16-28   ` ele(4)phant`

Match 3
Full match  35-44   `(x) fish `
Group 2.    35-38   `(x)`
Group 3.    36-37   `x`
Group 4.    38-44   ` fish `

The problem is that my regex seems to stop at the end of the line so the strings on the new line (dog, tiger, bird) are missing.

Do you have an idea how to also get the content of the next lines until the next match?

Upvotes: 1

Views: 118

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626689

You may use

'~^\(([^()]*)\)(.*(?:\R(?!\([^()]*\)).*)*)~m'

See the regex demo

Details

  • ^ - start of a line (due to m modifier, ^ matches the start of a line rather than the start of the whole string)

  • \( - a (

  • ([^()]*) - Group 1:
    • [^()]* - 0+ chars other than ( and ) (you might use your .*? here, if you do not want to overflow across lines, and want to match ( inside (...))
  • \) - a ) char
  • (.*(?:\R(?!\([^()]*\)).*)*) - Group 2:
    • .* - the rest of the line
    • (?:\R(?!\([^()]*\)).*)* - 0+ sequences of
      • \R(?!\([^()]*\)) - line break not followed with (...) substring
      • .* - rest of the line

Upvotes: 1

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