Reputation: 157
How to unlist list column and add new column from unlist column value in data frame.Can you please find my df below.
My data Frame.
Status AuditResult Deship Item
Active list(DDID=c("2","First"),Dvalue=c("Bpin","67")) list(UserID=1,Add="Stet,Bpin") list(Menu=1,Bill=9,Deship =list(list(IDesc ="A",vendor=5)))
Inactive list(DDID=c("Second","8"),Dvalue=c("CA","98")) list(UserID=2,Add="Stet,Bpin") list(Menu=1,Bill=8,Deship =list(list(IDesc ="B,N,O",vendor=4)))
OnHold list(DDID=c("78","8",NA),Dvalue=c("UK","76")) list(UserID=1,Add="Stet,Bpin") list(Menu=1,Bill=7,Deship =list(list(IDesc ="L,q",vendor=2)))
Expected data frame.
Status DDID Dvalue UserID Add Menu Bill IDesc vendor
Active "2","First" "Bpin","67" 1 "Stet,Bpin" 1 9 "A" 5
Inactive "Second","8" "CA","98" 2 "Stet,Bpin" 1 8 "B,N,O" 4
OnHold "78","8",NA "UK","76" 1 "Stet,Bpin" 1 7 "L,q" 2
please suggest me if any unstructured code.
Dput.
structure(list(Status = c("Active", "Inactive", "OnHold"), AuditResult = list(
structure(list(DDID = c(2, "First"), Dvalue = c("Bpin",
67)), .Names = c("DDID", "Dvalue"), class = "data.frame", row.names = 1:2),
structure(list(DDID = c("Second", 8), Dvalue = c("CA",
98)), .Names = c("DDID", "Dvalue"), class = "data.frame", row.names = 1:2),
structure(list(DDID = c("78","8",NA), Dvalue = c("UK",
76)), .Names = c("DDID", "Dvalue"), class = "data.frame", row.names = 1:2)),
Deship = list(structure(list(UserID = 1, Add = "Stet, Bpin"), .Names = c("UserID",
"Add"), class = "data.frame", row.names = 1L), structure(list(
UserID = 2, Add = "Stet, Bpin"), .Names = c("UserID",
"Add"), class = "data.frame", row.names = 1L), structure(list(
UserID = 1, Add = "Stet, Bpin"), .Names = c("UserID",
"Add"), class = "data.frame", row.names = 1L)), Item = list(
structure(list(Menu = 1, Bill = 9.0, Deship = list(
structure(list(IDesc = "A", vendor = 5), .Names = c("IDesc",
"vendor"), class = "data.frame", row.names = 1L))), .Names = c("Menu",
"Bill", "Deship"), class = "data.frame", row.names = 1L),
structure(list(Menu = 1, Bill = 8.0, Deship = list(
structure(list(IDesc = "B,N,O", vendor = 4), .Names = c("IDesc",
"vendor"), class = "data.frame", row.names = 1L))), .Names = c("Menu",
"Bill", "Deship"), class = "data.frame", row.names = 1L),
structure(list(Menu = 1, Bill = 7.0, Deship = list(
structure(list(IDesc = "L,q", vendor = 2), .Names = c("IDesc",
"vendor"), class = "data.frame", row.names = 1L))), .Names = c("Menu",
"Bill", "Deship"), class = "data.frame", row.names = 1L))), .Names = c("Status",
"AuditResult", "Deship", "Item"), row.names = c(NA,
3L), class = "data.frame")
Upvotes: 3
Views: 267
Reputation: 83235
As each of the list columns has a different structure, you'll have to deal with them in different ways.
With base R:
dfnew <- data.frame(df$Status,
do.call(rbind, lapply(df$AuditResult, function(x) sapply(x, toString))),
do.call(rbind, df$Deship),
do.call(rbind, lapply(df$Item, unlist)))
names(dfnew) <- sub('^.*\\.','',names(dfnew))
which gives:
> dfnew Status DDID Dvalue UserID Add Menu Bill IDesc vendor 1 Active 2, First Bpin, 67 1 Stet, Bpin 1 9 A 5 2 Inactive Second, 8 CA, 98 2 Stet, Bpin 1 8 B,N,O 4 3 OnHold 78, 8, NA UK, 76 1 Stet, Bpin 1 7 L,q 2
Upvotes: 2
Reputation: 39154
Assuming that the name of your data frame is called dt
, here is an option.
library(tidyverse)
dt2 <- dt %>%
select(Status, AuditResult) %>%
mutate(DDID = map(AuditResult, ~.$DDID),
Dvalue = map(AuditResult, ~.$Dvalue)) %>%
mutate(DDID = map_chr(DDID, ~toString(.)),
Dvalue = map_chr(Dvalue, ~toString(.))) %>%
select(-AuditResult)
dt3 <- dt %>%
select(Status, Deship) %>%
unnest()
dt4 <- dt %>%
select(Status, Item) %>%
unnest() %>%
unnest()
dt_final <- reduce(list(dt2, dt3, dt4), left_join, by = "Status")
dt_final
# Status DDID Dvalue UserID Add Menu Bill IDesc vendor
# 1 Active 2, First Bpin, 67 1 Stet, Bpin 1 9 A 5
# 2 Inactive Second, 8 CA, 98 2 Stet, Bpin 1 8 B,N,O 4
# 3 OnHold 78, 8, NA UK, 76 1 Stet, Bpin 1 7 L,q 2
Upvotes: 1