CODEWITHSUNDEEP
python
Lien
Lien

Reputation: 101

Python : how to count amount of letters of alphabet in string in parts

How to count the amount of letters in this string between the different parts? And the other way around: how to get the alphabetical string representation when the numbers are given?

Input: 'A-G H-O P Q-Z'

Output: (7, 8, 1, 10)

  q = list()

    for i in seq:
        if i is char:
            n = ord(i+1) - ord(i)
            q.append(n)

Upvotes: 0

Views: 295

Answers (2)

PythonProgrammi
PythonProgrammi

Reputation: 23443

a = "A-G  N B-Z"
a = a.split()
b = []
for i in a:
    b.extend([i.split("-")])
print(b)
for lists in b:
    if len(lists) > 1:
        print(lists, ":", ord(lists[1]) - ord(lists[0]) + 1)
    else:
        print(lists, ":", 1)

Output

[['A', 'G'], ['N'], ['B', 'Z']]
['A', 'G'] : 7
['N'] : 1
['B', 'Z'] : 25

Using list comprehension

a = "A-G  N B-Z"

b = [i.split("-") for i in a.split()]

print(b)
for lists in b:
    if len(lists) > 1:
        print(lists, ":", ord(lists[1]) - ord(lists[0]) + 1)
    else:
        print(lists, ":", 1)

Output

[['A', 'G'], ['N'], ['B', 'Z']]
['A', 'G'] : 7
['N'] : 1
['B', 'Z'] : 25

Upvotes: 0

s3bw
s3bw

Reputation: 3049

You can do this:

input_string = 'A-G H-O P Q-Z'
input_string = input_string.split()

q = []
for dletter in input_string:
    if '-' in dletter:
        q.append(1 + ord(dletter[2]) - ord(dletter[0]))
    else:
        q.append(1)

Alternatively without the if statement:

input_string = 'A-G H-O P Q-Z'
input_string = input_string.split()

q = []
for dletter in input_string:
    q.append(1 + ord(dletter[-1]) - ord(dletter[0]))

But this is a very good answer

Upvotes: 5

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