CODEWITHSUNDEEP
pythonfunctionfor-loop
user8929763
user8929763

Reputation: 21

Prime number test for numbers 1 - 1000

As a homework I have to write a prime number test, that gives back a "true" or "false" statement. The tricky thing is, I have to write a csv.-file that includes the "true" and "false" statements for the numbers 1 to 1000. I used this code for the prime number test

def Primzahl(n):
if n < 2:
    return False
if n == 2: 
    return True    
if not n & 1: 
    return False
for x in range(3, int(n**0.5) + 1, 2):
    if n % x == 0:
        return False
return True

and 

for i in range (1,1001):
    Primzahl (i)
    print (i)

My for-loop only gives out the numbers 1,1000 but not the true or false statements. Do I have to include if and else in my for loop? Can anyone help?

Upvotes: 1

Views: 222

Answers (2)

theMaestro73
theMaestro73

Reputation: 134

Currently you're only printing i, and not the return value from your method. You aren't doing anything with the return value from your method. You should assign the result to a variable and print the variable also. (You could also just call the method from within the print statement.)

for i in range (1,1001):
isPrime = Primzahl(i)
print (i + ": " + isPrime)

Upvotes: 0

Justin R.
Justin R.

Reputation: 24061

The problem is print(i). That will write i, which is the number from your range call. You will also need to print the value returned by your function, e.g. print(Primzahl(i)).

Upvotes: 3

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