CODEWITHSUNDEEP
batch-file
John
John

Reputation: 341

Count Directory Files then Test Numeric values

Using the code below I am able to count the number of files in a directory and call another batch file if the number of files in the directory equals (EQU or ==) say 20 When i use LSS i run into a few problems. The results are problematic and i am getting unexpected results depending on how many files are in the directory or the value of LSS If for example i have 9 files in my directory and LSS set for say 15 the call command doesn't work. Is there a way to fix this possible number Vs string issue. I have also tried using "" around the numbers but still no luck. Any help would be appreciated

@ECHO OFF

SETLOCAL 
SETLOCAL ENABLEDELAYEDEXPANSION

SET count=0 
for %%o IN (C:\test1\*.*) DO ( 
      echo %%o 
      SET /A count=count + 1 
)

echo %count%

IF %count% LSS 20 call RunAll.bat

ENDLOCAL ENABLEDELAYEDEXPANSION 
ENDLOCAL

Upvotes: 0

Views: 30

Answers (1)

user7818749
user7818749

Reputation:

you setlocal enabledelayedexpansion but you do not use its functionality. It makes more sense to wrap your if in double quotes or square brackets.

Lastly, no need to call RunAll.bat just can it without call.

@echo off
setlocal enabledelayedexpansion
set count=0 
for %%o in (F:\CSV\*) do ( 
      echo %%o
      set /A count=count + 1 
)
echo !count!
if "!count!" LSS "20" RunAll.bat
endlocal enabledelayedexpansion

Upvotes: 0

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