CODEWITHSUNDEEP
pythonpython-2.7dictionary
Joseph
Joseph

Reputation: 607

How to make certain values in dictionary add up to 100?

I have a dictionary with varying number of items. Each item can have a value of either a 1 or 0. Those with a value of 1 are stored in a list and counted. This is then used to calculate a percentage which would then be used to replace the value 1.

For example: if I have 10 items and only 7 contain a value of 1, the calculated percentage would be 100 / 7 = 14. Therefore those 7 items will have a new value of 14.

But there is a remainder left over and what I would like is for some items to gain this remainder (so 5 items would have a value of 14, 2 items would have a value of 15 so that (5 * 14) + (2 * 15) = 100.

How could this be done?

This is the code I used which gets the percentage value but I am unsure how to implement the remainder part (I would like to only show integers in the dictionary):

someDict = {
        'item_01': 0,
        'item_02': 0,
        'item_03': 0,
        'item_04': 1,
        'item_05': 1,
        'item_06': 1,
        'item_07': 1,
        'item_08': 1,
        'item_09': 1,
        'item_010': 1
        }

percentage_list = []
for key, value in someDict.items():
    if value == 1:
        percentage_list.append(value)

percentage_value = int(100) / int(len(percentage_list))
# =98

# Replace all 1's in someDict with percentage value
for key, value in someDict.items():
    if value == 1:
        someDict[key] = percentage_value

Upvotes: 0

Views: 221

Answers (2)

eugenhu
eugenhu

Reputation: 1238

If for some reason your remainder left over is such that each element may gain more than 1, just after calculating percentage_value:

num_divisions = len(percentage_list)

remainder = 100 - percentage_value * num_divisions

# Replace all 1's in someDict with percentage value
for i, key in enumerate(filter(lambda k: someDict[k] == 1, someDict)):
    extra = int(remainder/(num_divisions - i))

    someDict[key] = percentage_value + extra

    remainder -= extra

Upvotes: 2

mrCarnivore
mrCarnivore

Reputation: 5078

You should use // for int division and % for the remainder:

someDict = {
        'item_01': 0,
        'item_02': 0,
        'item_03': 0,
        'item_04': 1,
        'item_05': 1,
        'item_06': 1,
        'item_07': 1,
        'item_08': 1,
        'item_09': 1,
        'item_010': 1
        }

percentage_list = []
for key, value in someDict.items():
    if value == 1:
        percentage_list.append(value)

percentage_value = 100 // len(percentage_list)
remainder_value = 100 % len(percentage_list)

# Replace all 1's in someDict with percentage value
for key, value in someDict.items():
    if value == 1:
        if remainder_value > 0:
            someDict[key] = percentage_value + 1
            remainder_value -= 1
        else:
            someDict[key] = percentage_value

print(someDict)

Upvotes: 3

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