CODEWITHSUNDEEP
javascriptfunction
user2133404
user2133404

Reputation: 1857

Javascript accessing inner function from outside

I have the following json object

{
 ....
 ....
 data: function() {
    var x = 10;
    function isBig() {
        return x>6;
    }
    return x;
 }
}

I want the isBig to be a function inside data.

When I call data.isBig I am getting undefined and data.isBig() gives me an error saying isBig is not a function.

Upvotes: 0

Views: 74

Answers (2)

Jens Ingels
Jens Ingels

Reputation: 816

obj = {
	data: function(){
    	   var x = 10;
	   return this.isBig(x);
    },
	isBig: function(x){
           return x > 6;
    }
};

And if you want to reproduce the function but useally your better off with an contructor add that point. 

f = {
  isSmall: function(){},
  isBig: function(x){
    return x > 6;
  }
};
obj = {
  data: function(){
    var x = 10;
    return this.isBig(x);
  },
  isBig: f.isBig
};
obj.data();
obj.isBig(2);
f.isBig(2);

Upvotes: 0

steliosbl
steliosbl

Reputation: 8921

First of all, that is not JSON. It is an object. The way your object is structured currently, isBig is only accessible from inside data. If you want to access it outside data, the simplest way is to make it a property of the outer object:

{
    data: function()
    {
        var x = 10;
        return x;
    }
    isBig: function(x)
    {
        return x > 6;
    }
}

If you don't want to do that, then an alternative would be this:

{
    data: function()
    {
        var x = 10;
        this.isBig = function(x)
        {
            return x > 6;
        }
        return x;
    }
}

Calling data() works normally (returns 10), whereas calling new data() returns an object with a property isBig which corresponds to the function. This allows you to do this:

new myObj.data().isBig()

Upvotes: 3

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