CODEWITHSUNDEEP
regexbashfind
Eugeen
Eugeen

Reputation: 51

Regex in Bash: not wanting to include directories

I have a list of images, collected using the following line:

# find . -mindepth 1 -type f -name "*.JPG" | grep "MG_[0-9][0-9][0-9][0-9].JPG"

output:

./DCIM/103canon/IMG_0039.JPG
./DCIM/103canon/IMG_0097.JPG
./DCIM/103canon/IMG_1600.JPG
./DCIM/103canon/IMG_2317.JPG
./DCIM/IMG_0042.JPG
./DCIM/IMG_1152.JPG
./DCIM/IMG_1810.JPG
./DCIM/IMG_2564.JPG
./images/IMG_0058.JPG
./images/IMG_0079.JPG
./images/IMG_1233.JPG
./images/IMG_1959.JPG
./images/IMG_2012/favs/IMG_0039.JPG
./images/IMG_2012/favs/IMG_1060.JPG
./images/IMG_2012/favs/IMG_1729.JPG
./images/IMG_2012/favs/IMG_2013.JPG
./images/IMG_2012/favs/IMG_2317.JPG
./images/IMG_2012/IMG_0079.JPG
./images/IMG_2012/IMG_1403.JPG
./images/IMG_2012/IMG_2102.JPG
./images/IMG_2013/IMG_0060.JPG
./images/IMG_2013/IMG_1311.JPG
./images/IMG_2013/IMG_1729.JPG
./images/IMG_2013/IMG_2013.JPG
./IMG_0085.JPG
./IMG_1597.JPG
./IMG_2288.JPG

however I only want the very last portion, the IMG_\d\d\d\d.JPG. I have tried hundreds of regular expressions and this is the one that gives me the best result. Is there a way to only print out the filename without the directory tree before it or is is solely down to the regex?

Thanks

Upvotes: 0

Views: 38

Answers (2)

janos
janos

Reputation: 124824

If the -printf option is not available with your implementation of find (as in current versions of Mac OS X), then you can use -execdir echo {} \; instead (if that's available):

find . -mindepth 1 -type f -name "*MG_[0-9][0-9][0-9][0-9].JPG" -execdir echo {} \;

Upvotes: 0

hek2mgl
hek2mgl

Reputation: 158260

It should be

find . -mindepth 1 -type f -name "*MG_[0-9][0-9][0-9][0-9].JPG" -printf "%f\n"

Upvotes: 2

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