Reputation: 3578
I think this should be a bit tricky but somehow feasible, but I need help. I'd like to execute two functions from within my main() func. I'd like to be able to catch exceptions from the two separately, but still being able to execute both and get the result of at least one of them if the other raises an exception.
Let's say I have:
def foo():
raise TypeError
def bar():
return 'bar'
If I do (adapted from here):
def multiple_exceptions(flist):
for f in flist:
try:
return f()
except:
continue
def main():
multiple_exceptions([foo, bar])
main()
main()
would return 'bar'
, but I'd like to be able to still throw the exception from foo()
after all. This way, I would still have the result of one of my functions and the information on the error occurred in the other.
Upvotes: 0
Views: 2527
Reputation: 3578
Thanks for the comments. I solved by doing this:
def multiple_exceptions(flist):
exceptions = []
for f in flist:
try:
f()
except Exception as e:
exceptions.append(e.message)
continue
return exceptions
def main():
multiple_exceptions([foo, bar])
error_messages = main() # list of e.messages occurred (to be raised whenever I want)
Then I can raise my exception like e.g. raise Exception(error_messages[0])
(I only care about the first in this case let's say).
Upvotes: 0
Reputation: 704
You can capture and store the exceptions using 'as', e.g.:
try:
raise Exception('I am an error!')
print('The poster messed up error-handling code here.') #should not be displayed
except Exception as Somename:
print(Somename.message)
# you'll see the error message displayed as a normal print result;
# you could do print(stuff, file=sys.stderr) to print it like an error without aborting
print('Code here still works, the function did not abort despite the error above')
...or you can do:
except Exception as Somename:
do_stuff()
raise Somename
Upvotes: 1