Reputation: 1493
I have dataset like this:
{'project-1': [{'id':'1','name':'john'},{'id':'20','name':'steve'}],
'project-2': [{'id':'6','name':'jack'},{'id':'42','name':'anna'}]}
what I want to extract is the name of all people:
['john','steve','jack','anna']
How to get these list using python?
Upvotes: 1
Views: 27678
Reputation: 12689
Many solutions trying same old approach here using two loop
:
Here is different approach:
One line solution without any loop:
You can use lambda function with map:
data={'project-1': [{'id':'1','name':'john'},{'id':'20','name':'steve'}],
'project-2': [{'id':'6','name':'jack'},{'id':'42','name':'anna'}]}
print(list(map(lambda x:list(map(lambda y:y['name'],x)),data.values())))
output:
[['john', 'steve'], ['jack', 'anna']]
Upvotes: 1
Reputation: 733
name_id = {'project-1': [{'id':'1','name':'john'},{'id':'20','name':'steve'}], 'project-2': [{'id':'6','name':'jack'},{'id':'42','name':'anna'}]}
name_id['project-1'][0]['name'] = 'john'
name_id['project-1'][1]['name'] = 'steve'
name_id['project-2'][0]['name'] = 'jack'
name_id['project-2'][1]['name'] = 'anna'
The ['project-1']
gets the value corresponding to the project-1
key in the dictionary name_id
. [0]
is the list index for the first element in the dictionary value. ['name']
is also a key, but of the dictionary in the first element of the list. It gives you the final value that you want.
Upvotes: 0
Reputation: 300
This should do it.
d = {'project-1': [{'id':'1','name':'john'},{'id':'20','name':'steve'}],
'project-2': [{'id':'6','name':'jack'},{'id':'42','name':'anna'}]}
result = list()
for key in d:
for x in d[key]:
result.append(x['name'])
Upvotes: 1
Reputation: 11338
Iterate over the dict, then over the values of the current dict:
for d_ in d.values():
for item in d_:
print item['name']
Or in comprehension
names = [item['name'] for d_ in d.values() for item in d_]
print names
['john', 'steve', 'jack', 'anna']
Upvotes: 2
Reputation: 109756
my_dict = {
'project-1': [{'id':'1','name':'john'},{'id':'20','name':'steve'}],
'project-2': [{'id':'6','name':'jack'},{'id':'42','name':'anna'}]
}
You can use a list comprehension it get the name
field from each dictionary contained within the sublists (i.e. within the values of the original dictionary).
>>> [d.get('name') for sublists in my_dict.values() for d in sublists]
['john', 'steve', 'jack', 'anna']
Upvotes: 2