CODEWITHSUNDEEP
java
Stylised
Stylised

Reputation: 33

How to loop back to start of array after incorrect input

first post here. I was instructed to change my code to loop back to the beginning of the array and ask the user for input again after they input something invalid (Like 0 or 5 for example). If someone could point me in the right direction, I would be thankful.

package lepackage;
import java.util.Scanner;
public class SwitchItUp {
    public static void main(String[] args) {
    Scanner scanner = new Scanner(System.in);
       System.out.println("Enter menu item:");
       int input = scanner.nextInt();
        String inputString;
        switch (input) {
            case 1:  inputString = "User want to Enter data";
                     break;
            case 2:  inputString = "User want to Display sata";
                     break;
            case 3:  inputString = "User want to Print data";
                     break;
            case 4:  inputString = "User want to Exit";
                     break;
            default: inputString = "Invalid Number";
                     break;
        }
        System.out.println(inputString);
    }
}

Upvotes: 0

Views: 552

Answers (2)

Santanu Sahoo
Santanu Sahoo

Reputation: 1157

how about using a label here. though It's not the cleaner approach compare to do.. while. see the code . Also don't forget to close the scanner !!

 Scanner scanner = new Scanner(System.in);
        int input;
        badinput: while (true) {
            System.out.println("Enter menu item:");
            input = scanner.nextInt();
            String inputString;
            if ((!(input > 0 && input < 5)))
                continue badinput;
            else {
                switch (input) {
                //switch case
                }
                System.out.println(inputString);
                break;
            }

        }
        scanner.close();

Upvotes: 1

achAmh&#225;in
achAmh&#225;in

Reputation: 4266

I'd surround it with a do...while loop

do {
//your code here
} while (!(input > 0 && input < 5));

See it online!

Upvotes: 3

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