CODEWITHSUNDEEP
javascriptmutation-observers
David Pena
David Pena

Reputation: 163

MutationObserver for only the last mutation

I'm using the MutationObserver to save position changes in a draggable object.

It looks like this: 

 let observer = new MutationObserver( (mutations) => {
        mutations.forEach( (mutation) => {
            this.builderData[element.id].$position.left = element.style.left;
            this.builderData[element.id].$position.top = element.style.top;
            this.saveBuilderData();
        });
    });
    observer.observe(element, { attributes : true, attributeFilter : ['style'] });

However, this run for every pixel changed, so it is a lot saving operations being ran. I would like to only save after it has stop mutating for about 1 second, or that each callback excludes the previous one. I already did something like this with RxJava, but did not worked with MutationObserver.

Any ideas?

Upvotes: 5

Views: 3392

Answers (1)

Maluen
Maluen

Reputation: 1841

You could add a simple 1 second delay via setTimeout.

This way previous callbacks are discarded and the style is only changed after 1 second of inactivity:

let timer;
let observer = new MutationObserver( (mutations) => {
  if (timer) clearTimeout(timer);
  timer = setTimeout(() => {
    mutations.forEach( (mutation) => {
        this.builderData[element.id].$position.left = element.style.left;
        this.builderData[element.id].$position.top = element.style.top;
        this.saveBuilderData();
    });
  }, 1000);
});
observer.observe(element, { attributes : true, attributeFilter : ['style'] });

Upvotes: 8

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