CODEWITHSUNDEEP
pythonzipunzip
AsheKetchum
AsheKetchum

Reputation: 1108

Extracting inner file from zip file with python

I am able to extract the inner file, but it extracts the entire chain.
Suppose the following file structure

v a.zip
    v folder1
        v folder2
            > inner.txt

and suppose I want to extract inner.txt to some folder target.
Currently what happens when I try to do this is that I end up extracting folder1/folder2/inner.txt to target. Is it possible to extract the single file instead of the entire chain of directories? So that when target is opened, the only thing inside is inner.txt.

EDIT:
Using python zip module to unzip files and extract only the inner files to the desired location.

Upvotes: 0

Views: 11021

Answers (2)

CristiFati
CristiFati

Reputation: 41187

You should use the -j (junk paths (do not make directories)) modifier (old v5.52 has it). Here's the full list: [DIE.Linux]: unzip(1) - Linux man page, or you could simply run (${PATH_TO}/)unzip in the terminal, and it will output the argument list.

Considering that you want to extract the file in a folder called target, use the command (you may need to specify the path to unzip):

"unzip" -j "a.zip" -d "target" "folder1/folder2/inner.txt"

Output (Win, but for Nix it's the same thing):

(py35x64_test) c:\Work\Dev\StackOverflow\q047439536>"unzip" -j "a.zip" -d "target" "folder1/folder2/inner.txt"
Archive:  a.zip
  inflating: target/inner.txt

Output (without -j):

(py35x64_test) c:\Work\Dev\StackOverflow\q047439536>"unzip" "a.zip" -d "target" "folder1/folder2/inner.txt"
Archive:  a.zip
  inflating: target/folder1/folder2/inner.txt

Or, since you mentioned Python,

code00.py:

import os
from zipfile import ZipFile


def extract_without_folder(arc_name, full_item_name, folder):
    with ZipFile(arc_name) as zf:
        file_data = zf.read(full_item_name)
    with open(os.path.join(folder, os.path.basename(full_item_name)), "wb") as fout:
        fout.write(file_data)


if __name__ == "__main__":
    extract_without_folder("a.zip", "folder1/folder2/inner.txt", "target")

Upvotes: 2

Kemp
Kemp

Reputation: 3649

The zip doesn't have a folder structure in the same way as on the filesystem - each file has a name that is its entire path.

You'll want to use a method that allows you to read the file contents (such as zipfile.open or zipfile.read), extract the part of the filename you actually want to use, and save the file contents to that file yourself.

Upvotes: 1

Related Questions