CODEWITHSUNDEEP
pythonregex
haeny
haeny

Reputation: 363

extract string using regular expression

fix_release='Ubuntu 16.04 LTS'

p = re.compile(r'(Ubuntu)\b(\d+[.]\d+)\b')
fix_release = p.search(fix_release)
logger.info(fix_release) #fix_release is None

I want to extract the string 'Ubuntu 16.04'

But, result is None.... How can I extract the correct sentence?

Upvotes: 0

Views: 39

Answers (2)

Gurmanjot Singh
Gurmanjot Singh

Reputation: 10360

Try this Regex:

Ubuntu\s*\d+(?:\.\d+)?

Click for Demo

Explanation:

  • Ubuntu - matches Ubuntu literally
  • \s* - matches 0+ occurrences of a white-space, as many as possible
  • \d+ - matches 1+ digits, as many as possible
  • (?:\.\d+)? - matches a . followed by 1+ digits, as many as possible. A ? at the end makes this part optional.

Note: In your regex, you are using \b for the spaces. \b returns 0 length matches between a word-character and a non-word character. You can use \s instead

Upvotes: 1

akuiper
akuiper

Reputation: 215127

You confused the word boundary \b with white space, the former matches the boundary between a word character and a non word character and consumes zero character, you can simply use r'Ubuntu \d+\.\d+' for your case:

fix_release='Ubuntu 16.04 LTS'
p = re.compile(r'Ubuntu \d+\.\d+')
p.search(fix_release).group(0)
# 'Ubuntu 16.04'

Upvotes: 1

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