CODEWITHSUNDEEP
c
Tchaly Leandre Jr.
Tchaly Leandre Jr.

Reputation: 99

warning C4047: '=': 'char' differs in levels of indirection from 'char [2]'

Whenever I compile my program I get one error: warning C4047. I'm very new to programming in this language and don't understand what the problem is or how to fix it. Any help would be greatly appreciated thank you.

The error is specifically on line word[x - 1] = "i";

void RuleOne(char word[], char plural[]) {

    int x = strlen(word);

    word[x - 1] = "i";

    plural = strcat(word, "es");

}

Upvotes: 1

Views: 4446

Answers (2)

iBug
iBug

Reputation: 37227

word[x - 1] = "i";

"i" is a string literal, not a character constant.

Use single quotes if you want characters:

words[x - 1] = 'i';
               ^ ^

Besides, you're doing it wrong with plural. This is a wrong job:

plural = strcat(word, "es");

You're actually appending "es" to word and let the pointer plural point to the same address as word, which is obviously not what you intended to do. Try copying word the append es to the replica:

strcpy(plural, word);
strcat(plural, "es");

Since strcpy() returns the copied string (buffer), you can put it inside strcat():

strcat(strcpy(plural, word), "es");

Though, I recommend not doing so before you fully understand how it works.

Upvotes: 6

Déjà vu
Déjà vu

Reputation: 28830

There are two problems in your code

1) Indeed as iBug mentioned 

words[x - 1] = 'i'; // not "i"

2) plural is not set to the plural version

// instead of >> plural = strcat(word, "es");
strcpy(plural, word);
strcat(plural, "es");

is what you want.

Upvotes: 0

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