Reputation: 53
I created my application based on the Identity Framework, and create an interface ApplicationUser
to set the User_ID
type to GUID. All it's ok, but when I try to load the user using the UserManager
class, I get an exception that I cannot understand. I cannot understand why this column is added in the command
The exception:
ORA-00904: "Extent1"."ApplicationUser_Id": identificador inválido
The command that causes the exception:
SELECT
"Extent1"."ID_USER_CLAIM" AS "ID_USER_CLAIM",
"Extent1"."ID_USER" AS "ID_USER",
"Extent1"."CLAIM_TYPE" AS "CLAIM_TYPE",
"Extent1"."CLAIM_VALUE" AS "CLAIM_VALUE",
"Extent1"."ApplicationUser_Id" AS "ApplicationUser_Id"
FROM
"BEECORE"."ADM_USER_CLAIM" "Extent1"
WHERE
("Extent1"."ID_USER" = :p__linq__0)
The code:
var user = userService.UserManager.FindByName(model.UserName);
ApplicationUser:
using Microsoft.AspNet.Identity.EntityFramework;
using System;
namespace Bee.Core.Domain.Identity
{
public class ApplicationUser : IdentityUser<Guid, ApplicationUserLogin, ApplicationUserRole, ApplicationUserClaim>
{
public ApplicationUser()
{
Id = Guid.NewGuid();
}
public ApplicationUser(string name) : this() { UserName = name; }
}
}
Configuration:
using Bee.Core.Domain.Identity;
using System.Data.Entity.ModelConfiguration;
namespace Bee.Core.Administration.Data.EntityConfig.Identity
{
public class IdentityUserConfiguration : EntityTypeConfiguration<ApplicationUser>
{
public IdentityUserConfiguration()
{
ToTable("ADM_USER");
HasKey(c => new
{
c.Id
});
Property(c => c.Id).HasColumnName("ID_USER");
Property(c => c.Email).HasColumnName("EMAIL");
Property(c => c.EmailConfirmed).HasColumnName("EMAIL_CONFIRMED");
Property(c => c.PasswordHash).HasColumnName("PASSWORD_HASH");
Property(c => c.SecurityStamp).HasColumnName("SECURITY_STAMP");
Property(c => c.PhoneNumber).HasColumnName("PHONE_NUMBER");
Property(c => c.PhoneNumberConfirmed).HasColumnName("PHONE_NUMBER_CONFIRMED");
Property(c => c.TwoFactorEnabled).HasColumnName("TWO_FACTOR_ENABLED");
Property(c => c.LockoutEndDateUtc).HasColumnName("LOCKOUT_ENDDATEUTC");
Property(c => c.LockoutEnabled).HasColumnName("LOCKOUT_ENABLED");
Property(c => c.AccessFailedCount).HasColumnName("ACCESS_FAILED_COUNT");
Property(c => c.UserName).HasColumnName("USER_NAME");
}
}
}
Upvotes: 1
Views: 1465
Reputation: 146
I had the same problem when I have implemented custom Microsoft Identity. In that case, I needed to configure all foreign keys explicitly in EntityTypeConfiguration for each Identity class/table.
For example, your code need into class User (inherit - IdentityUser):
HasMany(x => x.Claims)
.WithRequired(y => y.ApplicationUser);
HasMany(x => x.Roles)
.WithRequired(y => y.ApplicationUser);
HasMany(x => x.Logins)
.WithRequired(y => y.ApplicationUser);
You need configure all the class Microsoft Identity with Foreign Key:
Class UserClaim (inherit - IdentityUserClaim):
HasRequired(x => x.ApplicationUser)
.WithMany(y => y.Claims)
.HasForeignKey(f => f.UserId);
Class Role (inherit - IdentityRole):
HasMany(c => c.Users).WithRequired().HasForeignKey(c => c.RoleId);
Class UserLogin (inherit - IdentityUserLogin):
HasRequired(x => x.ApplicationUser)
.WithMany(y => y.Logins)
.HasForeignKey(f => f.UserId);
Class UserRole (inherit - IdentityUserRole):
HasRequired(x => x.ApplicationUser)
.WithMany(y => y.Roles)
.HasForeignKey(f => f.UserId);
I hope have help you.
Upvotes: 2