Reputation: 315
I have the coordinates of 2 points A1 (x1,y1) and A2 (x2,y2) and a distance d. I need to find the coordinates of point A3 that is the distance d from point A2 on the linear graph defined by A1 and A2. How can i do that with JavaScript?
similar to https://softwareengineering.stackexchange.com/questions/179389/find-the-new-coordinates-using-a-starting-point-a-distance-and-an-angle
where the angle is known
Upvotes: 4
Views: 2294
Reputation: 1173
So you have to start from A1 and go to A2 direction by the distance between A1 and A2 + d
Assuming your point are objects of a Point class with x and y properties and a distance method you can do this:
function move_to(origin, direction, dist){
let dx = direction.x - origin.x;
let dy = direction.y - origin.y;
let coef = dist / origin.distance(direction);
let x = origin.x + dx * coef;
let y = origin.y + dy *coef;
return new Point(x, y)
}
move_to(A1, A2, A1.distance(A2) + d)
Here's a simple Point class implementation if you want:
class Point {
constructor(x, y){
this.x = x;
this.y = y;
}
distance(point){
return Math.sqrt((this.x - point.x) ** 2 + (this.y - point.y) ** 2)
}
}
Upvotes: 2
Reputation: 655
var A1 = {
x : 2,
y : 2
};
var A2 = {
x : 4,
y : 4
};
// Distance
var d= 2;
// Find Slope of the line
var slope = (A2.y-A1.y)/(A2.x-A1.x);
// Find angle of line
var theta = Math.atan(slope);
// the coordinates of the A3 Point
var A3x= A2.x + d * Math.cos(theta);
var A3y= A2.y + d * Math.sin(theta);
console.log(A3x);
console.log(A3y);
Upvotes: 9