Reputation: 339
I am a nebie to R.I have a data table DT as
id time day type
1 1 9 10
2 2 3 10
1 3 6 12
3 8 9 10
6 9 9 10
8 2 6 18
9 3 5 10
9 1 4 12
From this I initially wanted the count group by day time type.SO i did
DT[,.N,by=list(day,time,type)]
which gives the count for each group.
Now I need to calculate the variance for each group. So I tried
DT[,var(.N),by=list(day,time,type)]
But this gave NA for all fields.Any help is appreciated.
Upvotes: 0
Views: 1149
Reputation: 56
In the example given, there is only a single unique value for many of the combinations, so there is no variance for those rows.
DT <- data.frame (id = c(1,2,1,3,6,8,9,9),
time = c(1,2,3,8,9,2,3,1),
day = c(9,3,6,9,9,6,5,4),
type = c(10,10, 12, 10,10,18,10,12))
aggregate(DT, list(DT$id), FUN = var)
Upvotes: 1