CODEWITHSUNDEEP
mysqlgroup-bygrouping
Lizard
Lizard

Reputation: 45062

Group by a range of X days

I have a set or records and I want to count and group them by a certain range e.g. I want to count the records that were created by groups of X days

e.g. SELECT COUNT(*) FROM `table` GROUP BY /*`created` 3 days/*

Upvotes: 6

Views: 5683

Answers (3)

Peigong
Peigong

Reputation: 171

Thanks @Ronnis, I use your example and finally solve my problem.

And there is a small mistake I found, in example, I add one row 

insert into t1(created) values (date '2011-01-21')

Now I get:

+----------+--------------+--------------+----------+
| days_ago | min(created) | max(created) | count(*) |
+----------+--------------+--------------+----------+
|     1986 | 2011-01-20   | 2011-01-21   |        2 |
|     1989 | 2011-01-17   | 2011-01-19   |        3 |
|     1992 | 2011-01-14   | 2011-01-16   |        3 |
|     1995 | 2011-01-11   | 2011-01-13   |        3 |
|     1998 | 2011-01-09   | 2011-01-10   |        2 |
+----------+--------------+--------------+----------+

As you can see that days divide into 2, 3, 3, 3, 2 which not what I expected.

I change SQL as 

select floor(datediff(created, '2011-01-09') / 3) * 3 as days_before
      ,min(created)
      ,max(created)
      ,count(*)
from t1
group by floor(datediff(created, '2011-01-09') / 3);

Just get datediff from created to start date, and now I get:

+-------------+--------------+--------------+----------+
| days_before | min(created) | max(created) | count(*) |
+-------------+--------------+--------------+----------+
|           0 | 2011-01-09   | 2011-01-11   |        3 |
|           3 | 2011-01-12   | 2011-01-14   |        3 |
|           6 | 2011-01-15   | 2011-01-17   |        3 |
|           9 | 2011-01-18   | 2011-01-20   |        3 |
|          12 | 2011-01-21   | 2011-01-21   |        1 |
+-------------+--------------+--------------+----------+

That might be more suitable.

Upvotes: 2

Ronnis
Ronnis

Reputation: 12843

Here is an example with dates.

create table t1(created date not null);

insert 
  into t1(created) values (date '2011-01-09')
                         ,(date '2011-01-10')
                         ,(date '2011-01-11')
                         ,(date '2011-01-12')
                         ,(date '2011-01-13')
                         ,(date '2011-01-14')
                         ,(date '2011-01-15')
                         ,(date '2011-01-16')
                         ,(date '2011-01-17')
                         ,(date '2011-01-18')
                         ,(date '2011-01-19')
                         ,(date '2011-01-20');

select floor(datediff(now(), created) / 3) * 3 as days_ago
      ,min(created)
      ,max(created)
      ,count(*)
  from t1
 group 
    by floor(datediff(now(), created) / 3);

+----------+--------------+--------------+----------+
| days_ago | min(created) | max(created) | count(*) |
+----------+--------------+--------------+----------+
|        0 | 2011-01-18   | 2011-01-20   |        3 |
|        3 | 2011-01-15   | 2011-01-17   |        3 |
|        6 | 2011-01-12   | 2011-01-14   |        3 |
|        9 | 2011-01-09   | 2011-01-11   |        3 |
+----------+--------------+--------------+----------+
4 rows in set (0.00 sec)

Upvotes: 8

Sam Dufel
Sam Dufel

Reputation: 17608

You can do something like
SELECT COUNT(*) FROM table GROUP BY FLOOR(created / 3)

... I think.

Although if created is a date field, you'll have to do a little more jiggering to get it into a number value for this to work.

Upvotes: 4

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