CODEWITHSUNDEEP
pythonloopsdictionaryiterator
NorthIsUp
NorthIsUp

Reputation: 17877

Identify which iteration you are on in a loop in python

Basically I would like to be able to tell when I'm on the Nth item in a loop iteration. Any thoughts?

d = {1:2, 3:4, 5:6, 7:8, 9:0}

for x in d:
    if last item: # <-- this line is psuedo code
        print "last item :", x
    else:
        print x

Upvotes: 14

Views: 24871

Answers (5)

kungfooman
kungfooman

Reputation: 4892

list = [1,2,3]

last = list[-1]

for i in list:
    if i == last:
        print("Last:")
    print i

Output:

1
2
Last:
3

Warning: Only works when the last two elements are not equal

Upvotes: 0

Apalala
Apalala

Reputation: 9244

for x in d.keys()[:-1]:
    print x
if d: print "last item:", d.keys()[-1]

Upvotes: 3

miku
miku

Reputation: 188134

Use enumerate:

#!/usr/bin/env python

d = {1:2, 3:4, 5:6, 7:8, 9:0}

# If you want an ordered dictionary (and have python 2.7/3.2), 
# uncomment the next lines:

# from collections import OrderedDict
# d = OrderedDict(sorted(d.items(), key=lambda t: t[0]))

last = len(d) - 1

for i, x in enumerate(d):
    if i == last:
        print i, x, 'last'
    else:
        print i, x

# Output:
# 0 1
# 1 3
# 2 9
# 3 5
# 4 7 last

Upvotes: 31

eyquem
eyquem

Reputation: 27585

d = {1:2, 3:4, 5:6, 7:8, 9:0}

for i,x in enumerate(d):
    print "last item :"+repr(x) if i+1==len(d) else x

But the last item of an unordered dictionary doesn't mean anything

Upvotes: 1

user225312
user225312

Reputation: 131767

How about using enumerate?

>>> d = {1:2, 3:4, 5:6, 7:8, 9:0}
>>> for i, v in enumerate(d):
...     print i, v              # i is the index
... 
0 1
1 3
2 9
3 5
4 7

Upvotes: 6

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