Reputation: 89
I have a list of responses to 7 questions from a survey, each their own column, and am trying to find the response within the first 6 that is closest (numerically) to the 7th. Some won't be the exact same, so I want to create a new variable that produces the difference between the closest number in the first 6 and the 7th. The example below would produce 0.
s <- c(1,2,3,4,5,6,3)
s <- t(s)
s <- as.data.frame(s)
s
Any help is deeply appreciated. I apologize for not having attempted code as nothing I have tried has actually gotten close.
Upvotes: 1
Views: 115
Reputation: 868
How about this?
which.min( abs(s[1, 1:6] - s[1, 7]))
I'm assuming you want it generalized somehow, but you'd need to provide more info for that. Or just run it through a loop :-)
EDIT: added the loop from the comment and changed exactly 2 tiny things.
s <- c(1,2,3,4,5,6,3)
t <- c(1,2,3,4,5,6,7)
p <- c(1,2,3,4,5,6,2)
s <- data.frame(s,t,p)
k <- t(s)
k <- as.data.frame(k)
k$t <- NA ### need to initialize the column
for(i in 1:3){
## need to refer to each line of k when populating the t column
k[i,]$t <- which.min(abs(k[i, 1:6] - k[i, 7])) }
Upvotes: 2