CODEWITHSUNDEEP
linuxcurlcommand-lineterminal
Chase
Chase

Reputation: 135

Using an "if" statement with curl in terminal?

I'm using this command to get the response code of a page using curl:

curl -s -o /dev/null -w "%{http_code}" 'https://www.example.com'

If the response code is 200, then I want to delete a certain file on my computer. If it isn't 200, nothing should be done.

What's the easiest way to do this?

Upvotes: 4

Views: 7022

Answers (1)

randomir
randomir

Reputation: 18697

You can store the result in a shell variable (via command substitution), and then test the value with a simple if and [[ command. For example, in bash:

#!/bin/bash
code=$(curl -s -o /dev/null -w "%{http_code}" 'https://www.example.com')
if [[ $code == 200 ]]; then
    rm /path/to/file
    # other actions
fi

If all you want is a simple rm, you can shorten it to:

#!/bin/bash
[[ $code == 200 ]] && rm /path/to/file

In a generic POSIX shell, you'll have to use a less flexible [ command and quote the variable:

#!/bin/sh
code=$(curl -s -o /dev/null -w "%{http_code}" 'https://www.example.com')
if [ "$code" = 200 ]; then
    rm /path/to/file
fi

Additionally, to test for a complete class of codes (e.g. 2xx), you can use wildcards:

#!/bin/bash
[[ $code == 2* ]] && rm /path/to/file

and the case command (an example here).

Upvotes: 9

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