Reputation: 299
DELIMITER $$
DROP PROCEDURE IF EXISTS `user_db`.`insertUser` $$
CREATE PROCEDURE `user_db`.`insertUser`(
IN _userEmail VARCHAR(50),
IN _userPassword VARCHAR(50),
IN _userPhone VARCHAR(10),
IN _userUsername VARCHAR(50),
IN _userAccountType ENUM('0', '1'),
IN _userAdmin ENUM('0', '1'),
IN _userSuperAdmin ENUM('0', '1'),
IN _userPresenceState ENUM('0', '1'),
OUT _userInsertResult INT(36)
)
NOT DETERMINISTIC MODIFIES SQL DATA SQL SECURITY DEFINER
BEGIN
DECLARE _userCount INT;
SELECT COUNT(id) AS _userCount FROM `user_db`.`user_primary` WHERE email = _userEmail LIMIT 1;
IF _userCount = 0 THEN
INSERT INTO `user_db`.`user_primary` (id, email, encrypted_password, phone, username, user_account_type, user_admin, user_super_admin, presence_state) VALUES (UUID(), _userEmail, _userPassword, _userPhone, _userUsername, _userAccountType, _userAdmin, _userSuperAdmin, _userPresenceState);
SET _userInsertResult := LAST_INSERT_ID();
END IF;
END
$$
DELIMITER ;
I wrote this stored procedure in MYSQL to check if the user exist and if the count is 0 then insert and return the id
else I'll do something else. But even if the _userCount
is 0
, the INSERT
statement is not working. This is my first stored procedure and I'm learning. I'm trying but not able to understand the reason for failure.
Upvotes: 1
Views: 1042
Reputation: 15941
An alternative answer is to tweak your logic a bit, replacing this
SELECT COUNT(id) AS _userCount
FROM `user_db`.`user_primary`
WHERE email = _userEmail LIMIT 1;
IF _userCount = 0 THEN
with
IF NOT EXISTS (SELECT * FROM `user_db`.`user_primary` WHERE email = _userEmail) THEN
Upvotes: 0
Reputation: 562330
You want:
SELECT COUNT(id) INTO _userCount FROM ...
Merely using AS
just declares a column alias for the COUNT(id) expression, it doesn't assign the result to a variable of the same name as the alias.
So in your procedure, the variable _userCount is never assigned a value, and so the statement inside your IF block never runs.
P.S.: This has nothing to do with your question, but I noticed you are using INT(36). The argument to INT doesn't do anything. It doesn't make the INT larger or able to accept 36-digit numbers. See my answer to Types in MySQL: BigInt(20) vs Int(20)
Upvotes: 3