CODEWITHSUNDEEP
compiler-errorsperf
Wind
Wind

Reputation: 31

Perf Compilation exception with SYS_futex

I want to compile a perf using the Linux source code(tools/perf/). But it failed when I make. Below is the error output. And I don't modify anything for the Linux source code(kernel-3.10-327.36.3.el7.x86_64). I use the centos7.2 and the kernel version is 3.10-327.36.3.el7.x86_64.

In file included from bench/futex-hash.c:17:0:
bench/futex.h: In function ‘futex_wait’:
bench/futex.h:36:10: error: ‘SYS_futex’ undeclared (first use in this function)
  syscall(SYS_futex, uaddr, op | opflags, val, timeout, uaddr2, val3)
          ^

bench/futex.h:45:9: note: in expansion of macro ‘futex’
  return futex(uaddr, FUTEX_WAIT, val, timeout, NULL, 0, opflags);
         ^

bench/futex.h:36:10: note: each undeclared identifier is reported only once for each function it appears in
  syscall(SYS_futex, uaddr, op | opflags, val, timeout, uaddr2, val3)

Upvotes: 1

Views: 764

Answers (1)

肖海飚
肖海飚

Reputation: 36

It has been a long time since the question is asked, but there are still many people who are troubled by this, like me. I wasted a lot of time on this. And finally I solve the question by adding a patch. you can reference https://lore.kernel.org/patchwork/patch/850380/

Upvotes: 2

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