Reputation: 9
I have a table that have date grouped. I need to select only groups that have positive and negative value inside. For example:
id value1
2 7
2 8
2 -1
3 3
3 4
4 -1
4 -2
5 7
5 -5
the result should be
id value1
2 7
2 8
2 -1
5 7
5 -5
because the group with id 3 just have positive number and the group with id 4 just have negative number.
any idea how can I do it using case (when then) in a select or using if else inside a function. Or any other idea?
Upvotes: 0
Views: 651
Reputation: 31648
Try this.
select id,value1 FROM
(
select t.*,
count( DISTINCT SIGN (value1 ) ) OVER (PARTITION BY id ) n
from yourtable t
) WHERE n = 2
;
The Sign()
function gives 1 for positive and -1 for negative numbers.
Upvotes: 1
Reputation: 12833
If you group by the ID, you can use the aggregate functions MIN and MAX to find out if there are both positive and negative values. You need to decide how to treat 0
though... I have treated it as positive below :)
with your_table as(
-- Your example data here, this is not really part of the solution
select 2 as id, 7 as value1 from dual union all
select 2 as id, 8 as value1 from dual union all
select 2 as id, -1 as value1 from dual union all
select 3 as id, 3 as value1 from dual union all
select 3 as id, 4 as value1 from dual union all
select 4 as id, -1 as value1 from dual union all
select 4 as id, -2 as value1 from dual union all
select 5 as id, 7 as value1 from dual union all
select 5 as id, -5 as value1 from dual
)
select *
from your_table
where id in(select id
from your_table
group by id
having min(value1) < 0
and max(value1) >= 0);
Upvotes: 0