CODEWITHSUNDEEP
phppreg-replace
Laurent
Laurent

Reputation: 1563

PHP preg_replace image names

I'm trying to replace image names within a page by using preg_replace but I'm probably missing something with regular expressions.

For the sake of the example, I'll use the following page: https://www.laurentwillen.be/circuits/circuit-autriche/alpbach/

So here is what I do:

$media = get_attached_media( 'image', $metadata["page_id"] );
foreach ($media as $key=>$value)
{
    $old_image = explode("/",$media[$key]->guid);
    $old_image = $old_image[sizeof($old_image)-1];
    $old_image = explode(".",$old_image);
    $old_image = "/".$old_image[0]."/";
    $new_image = wp_get_attachment_image_src($key,'tablet');
    $new_image = explode ("/",$new_image[0]);
    $new_image = $new_image[sizeof($new_image)-1];
    $new_image = explode (".",$new_image);
    $new_image = "/".$new_image[0]."/";
    preg_replace($old_image,$new_image,$content,-1,$count);
}

To spare you the trouble of guessing the variable values, here is what $old_image and $new_image represent for the page given higher:

$old_image values:

/alpbach-photo-1/
/alpbach-photo-2/
/alpbach-photo-3/
/alpbach-photo-4/
/alpbach-photo-5/
/alpbach-photo-6/
/alpbach-photo-top/

$new_image values:

alpbach-photo-1-900x600
alpbach-photo-2-900x600
alpbach-photo-3-900x600
alpbach-photo-4-900x600
alpbach-photo-5-900x600
alpbach-photo-6-900x600
alpbach-photo-top-900x281

The count for preg_replace returns 

9
0
9
0
9
0
0

But in the end, nothing is replaced.

If I try manually this:

preg_replace("/alpbach-photo-3/","/alpbach-photo-1/",$content,-1,$count);

Nothing is replaced either.

What am I doing wrong? Any idea?

Thanks!

Upvotes: 0

Views: 170

Answers (1)

silentavt
silentavt

Reputation: 876

As php manual says:

preg_replace() returns an array if the subject parameter is an array, or a string otherwise.

If matches are found, the new subject will be returned, otherwise subject will be returned unchanged or NULL if an error occurred.

So you need to store the result of preg_replace into some variable.

$result = preg_replace($old_image,$new_image,$content,-1,$count);

Upvotes: 1

Related Questions