CODEWITHSUNDEEP
pythonarrays
Vish01
Vish01

Reputation: 25

Python list to tuple

I have this :

(([75, 0], [100, 0], [100, 370]), ([75, 0], [100, 370], [75, 370]))

that come from this : 

 [(array([75,  0]), array([100,   0]), array([100, 370])), (array([75,  0]), array([100, 370]), array([ 75, 370]))]

and I want to have : 

[(x1, y1, x2 , y2 ,x3 ,y3), (x1, y1, x2 , y2 ,x3 ,y3), ...]

or

[(75, 0, 100, 0, 100, 370), (75, 0, 100, 0, 100, 370),.....]

Thanks for the help!

Upvotes: 2

Views: 77

Answers (4)

Emily
Emily

Reputation: 346

Easy to understand version:

original = (([75, 0], [100, 0], [100, 370]), ([75, 0], [100, 370], [75, 370]))
final = []
for each_tuple in original:
    final_child_list = []
    for each_list in each_tuple:
        final_child_list.extend(each_list)
    final.append(final_child_list)

You'll get:

>>> final
[[75, 0, 100, 0, 100, 370], [75, 0, 100, 370, 75, 370]]
# if you prefer the inside element to be tuples
>>> [tuple(x) for x in final]
[(75, 0, 100, 0, 100, 370), (75, 0, 100, 370, 75, 370)]

There might be shorter versions using list comprehension, but less readability.

Upvotes: 0

Mateen Ulhaq
Mateen Ulhaq

Reputation: 27251

Starting with this example:

from operator import add
from functools import reduce

reduce(add, (x for x in [[1, 2], [3, 4]]))

Outputs:

[1, 2, 3, 4]

Now just do this for each element in the tuple:

[tuple(reduce(add, x)) for x in data]

Outputs:

[(75, 0, 100, 0, 100, 370), (75, 0, 100, 370, 75, 370)]

Upvotes: 0

Francisco
Francisco

Reputation: 11496

You could use a list comprehension:

>>> t = (([75, 0], [100, 0], [100, 370]), ([75, 0], [100, 370], [75, 370])) 
>>> [tuple(sub for el in l for sub in el) for l in t]
[(75, 0, 100, 0, 100, 370), (75, 0, 100, 370, 75, 370)]

Upvotes: 2

Ajax1234
Ajax1234

Reputation: 71471

You can use itertools.chain:

import itertools
s = (([75, 0], [100, 0], [100, 370]), ([75, 0], [100, 370], [75, 370])) 
final_s = [list(itertools.chain.from_iterable(i)) for i in s]

Output:

[[75, 0, 100, 0, 100, 370], [75, 0, 100, 370, 75, 370]]

or using reduce in Python2:

s = (([75, 0], [100, 0], [100, 370]), ([75, 0], [100, 370], [75, 370]))    
new_s = [reduce(lambda x, y:list(x)+list(y), i) for i in s]

Output:

[[75, 0, 100, 0, 100, 370], [75, 0, 100, 370, 75, 370]]

Upvotes: 3

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