Reputation: 149
I didnt succeed writing an approriate batch file and would appreciate some help.
Let's say I have an exe in D:\Test\ called script.exe. To execute this script.exe it requires an additional argument of a .bin files (e.g. bin01.bin, bin02.bin).
Therefore it would be like: script.exe -i bin01.bin, script.exe -i bin01
I want the script to execute with all .bin files from all subfolders
D:\Test\script.exe
D:\Test\Folder01\bin01.bin
D:\Test\Folder01\bin02.bin
D:\Test\Folder02\bin01.bin
D:\Test\Folder03\bin01.bin
anyone could help me here? Thanks a lot in advance.
Upvotes: 4
Views: 23083
Reputation: 49096
For direct execution from within a command prompt window:
for /R "D:\Test" %I in (*.bin) do @D:\Test\script.exe -i "%I"
And the same command line for usage in a batch file:
@for /R "D:\Test" %%I in (*.bin) do @D:\Test\script.exe -i "%%I"
The command FOR searches recursive in directory D:\Test
and all subdirectories for files matching the wildcard pattern *.bin
.
The name of each found file is assigned with full path to case-sensitive loop variable I
.
FOR executes for each file the executable D:\Test\script.exe
with first argument -i
and second argument being the name of found file with full path enclosed in double quotes to work for any *.bin file name even those containing a space or one of these characters: &()[]{}^=;!'+,`~
.
@
at beginning of entire FOR command line just tells Windows command interpreter cmd.exe
not to echo the command line after preprocessing before execution to console window as by default.
@
at beginning of D:\Test\script.exe
avoids the output of this command to console executed on each iteration of the loop.
Most often the echo of a command line before execution is turned off at beginning of the batch file with @echo off
as it can be seen below.
@echo off
for /R "D:\Test" %%I in (*.bin) do D:\Test\script.exe -i "%%I"
For understanding the used commands and how they work, open a command prompt window, execute there the following commands, and read entirely all help pages displayed for each command very carefully.
echo /?
for /?
Upvotes: 10