CODEWITHSUNDEEP
pythoninputinteger
N. Bartos
N. Bartos

Reputation: 13

input as float or int

I would like to be able to display double the value of any number the user inputs.

spam = int(input('choose any number: '))
print('Your number doubled is: ' + str(spam*2))

The problem is if the user inputs a decimal, ie 3.4. It comes up with an error since it becomes a float value.

Traceback (most recent call last):
  File "<pyshell#66>", line 1, in <module>
    spam = int(input('choose any number: '))
ValueError: invalid literal for int() with base 10: '3.4'

Is there a simple way to let the user input any number (be it integer or float value)?

This is in python 3, so raw_input doesn't work.

Upvotes: 1

Views: 109

Answers (2)

HowdyshorjBlender
HowdyshorjBlender

Reputation: 31

Do this:

spam = input('choose any number: ')

try:
        print('Your number doubled is: ' ,int(spam)*2)


except ValueError:
        print('Your number doubled is: ' ,float(spam)*2)

The way this works is that it will try to convert into an integer, and if that doesn't work it will convert it into a float.

Upvotes: 0

Reblochon Masque
Reblochon Masque

Reputation: 36702

You could use float:

spam = float(input('choose any number: '))
print('Your number doubled is: ' + str(spam*2))

Upvotes: 0

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