CODEWITHSUNDEEP
pythonpython-3.xcomparison-operators
alec_djinn
alec_djinn

Reputation: 10779

Confusing comparison output

I am confused about the following:

>>> 1,2 == 1,2
(1, False, 2)

The == operator should return only a bool (or at least I thought so). I would have expected to have, (True, True) assuming that the line would have been processed like a,b = 1,2 but performing comparison instead of assignment. Or, to have an error. But definitely not (1, False, 2).

Can anyone explain what is going on here?

Upvotes: 0

Views: 43

Answers (2)

shubham katariya
shubham katariya

Reputation: 11

@alec_djinn

comparison operator work If the values of two operands are equal, then the condition becomes true.

you are trying to compare wrong data type 1,2 is not valid.

try '1,2' == '1,2' will give you correct results.

1,2 is not single argument.

Upvotes: -1

Dimitris Fasarakis Hilliard
Dimitris Fasarakis Hilliard

Reputation: 160377

This:

1,2 == 1,2

is evaluated as a three element tuple that contains 1, 2 == 1 and 2 respectively. You need to use a couple of parentheses here:

(1, 2) == (1, 2)

This is stated in the Language Reference:

Except when part of a list or set display, an expression list containing at least one comma yields a tuple. The length of the tuple is the number of expressions in the list. The expressions are evaluated from left to right.

Upvotes: 2

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