CODEWITHSUNDEEP
c++floating-point-exceptions
Abdullah Nawaz Khan
Abdullah Nawaz Khan

Reputation: 21

Floating point exception error while finding ''Perfect Number" using user defined functions

I have to write a program with checks "Perfect Numbers" in a specific range given by the user. I made a user-defined function to check if a particular number is a perfect number. If it is then 1 is returned, if not then 0. And then I use an if statement to print out the perfect number in the main program. The issue I'm getting is a floating point exception error. I have no idea what to do now. I'll be really grateful for some help. :).

#include <iostream>
using namespace std;

int isPerfect(int n);

int main(){
    int num=0,perfectCheck=0;
    cout<<"Enter a value for N: ";
    cin>>num;
    cout<<"Perect numbers between 1 and "<<num<<" are : "<<endl;
    for(int i;i<=num;i++){
        perfectCheck=isPerfect(i);
        if(perfectCheck==1){
              cout<<i<<endl;
        }   
    }
    return 0;
}

int isPerfect(int n){
    int sum,mod;
    for(int i;i<n;i++){
        mod=n%i;
        if(mod==0){
            sum=sum+i;
        }
    }
    if(sum==n){
         return 1;
    }
    else{
        return 0;
    }
}

Upvotes: 0

Views: 71

Answers (1)

DPDP
DPDP

Reputation: 403

Your for loop in isPerfect function should start from 1, because n%0 is undefined behavior.

Upvotes: 1

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