CODEWITHSUNDEEP
javalogarithm
Haruki
Haruki

Reputation: 109

Converting linear scale to log scale in java

I looked and found one post which helped me here: Convert Linear scale to Logarithmic

However I either did some mistake I can't find or I got wrong idea of the formula. I want to convert any number from linear 1-256 range to their respective values if it was logarithmic scale. Can someone help me to correct my code? When i try values low values from zero it works kind of fine but trying to convert anything over 160 gets me result which is > 256. Here is my code:

package linear2log;

public class Linear2Log {

    public static void main(String[] args) {

        System.out.println("Ats3: " + lin2log(160));
    }

    public static long lin2log(int z) {
        int x = 1;
        int y = 256;
        double b = Math.log(y/x)/(y-x);
        double a = 10 / Math.exp(b*10);
        double tempAnswer = a * Math.exp(b*z);
        long finalAnswer = Math.max(Math.round(tempAnswer) - 1, 0);

        return finalAnswer;
    }
}

Upvotes: 1

Views: 3531

Answers (1)

Luk
Luk

Reputation: 2246

You get the formula wrong.

For sure this line 

double a = 10 / Math.exp(b*10);

You are using value 10 from example, but you should be using your value which is 256.

double a = y / Math.exp(b * y);

I don't get why are you using this line: 

 long finalAnswer = Math.max(Math.round(tempAnswer) - 1, 0);

This way you are always getting value that is one less than actual value.

Upvotes: 1

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