CODEWITHSUNDEEP
phparrays
Al Amin
Al Amin

Reputation: 54

Call array variable inside of array in php

I want to call array variable inside the current array. Something like this:

$conv= array (
"hello" => array("Hello", "Hi", "Hello, how are you?"),
"helo" => array_merge($conv['hello'])
);
print_r($conv['helo']);

How can I do this. thanks.

Upvotes: 1

Views: 175

Answers (2)

DrKey
DrKey

Reputation: 3495

If you want to define your function directly when you create the array, then you need to declare helo value as anonymous function, refer current array as global variable and return something you need

$conv = array(
"hello" => array("Hello", "Hi", "Hello, how are you?"),
"helo" => function() {
        global $conv;
        return array_merge($conv['hello'], array("Bye", "See you"));
    }
);
print_r($conv['helo']());

Note that when you need the value returned from that function you need to call it as a function like above $conv['helo']() while calling just $conv['helo'] will return a Closure object.

UPDATE

According to what you're asking in comments, it seems that you just want to get a copy of hello value through a function

$conv = array(
"hello" => array("Hello", "Hi", "Hello, how are you?"),
"helo" => function() {
        global $conv;
        return $conv["hello"];
    }
);
print_r($conv['helo']());

Upvotes: 2

Andreas
Andreas

Reputation: 23958

The way you try to build the array is probably impossible.
Because the array is not made untill the end of the function ; when you try to set 'helo', 'hello' is undefined.

You need to set 'hello' first then copy it to 'helo'. 

$conv = array("hello" => array("Hello", "Hi", "Hello, how are you?"));

$conv["helo"] = $conv['hello'];
print_r($conv['helo']);

https://3v4l.org/PCJH7

Upvotes: 0

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