CODEWITHSUNDEEP
pythonlist
user9059368
user9059368

Reputation: 21

Find nearest value for 3 lists

Here is my code to get the nearest value to a given number ( Mynumber) from a list (Mylist)

    Mylist= [ 1, 2, 3]
    Mynumber=3

    takeClosest = lambda num,collection:min(collection,key=lambda x:abs(x-
    num))
    closest= [takeClosest(Mynumber,Mylist)]

    print closest

Now I have 3 lists [ 1, 2, 3] ,[ 4, 7, 8], [ 13, 9, 10] I want to compare first item , second item and 3rd item of them with this list,[2,6,9] ,If I compare 1st item in each list, out if [1,4,13], 1 is the closest to 2 ,If I compare 2nd item in each list, out of [2,7,9], 7 is the closest to 6,If I compare 3rd item in each list, out of [3,8,10], 10 is the closest to 9 Does any one know how to do it? Any suggestion would be greatly appreciated

    """
    Mylist1= [ 1, 2, 3]
    Mylist2= [ 4, 7, 8]
    Mylist3= [ 13, 9, 10]

    Mynumber=[2,6,9]
    """

Upvotes: 0

Views: 81

Answers (3)

Aaditya Ura
Aaditya Ura

Reputation: 12679

You can try something like this:

data=[ 1, 2, 3] ,[ 4, 7, 8], [ 13, 9, 10]
true1=[2,6,9]
for i in zip(*data,true1):
    print(min([(abs(k - i[-1:][0]), k, i[-1:][0]) for k in i[:-1]])[1:])

Note that in last item [3,8,10] 8 is close to 9 :

output:

(1, 2)
(7, 6)
(8, 9)

Upvotes: 0

user2390182
user2390182

Reputation: 73480

You could just do this using map and the zip(*...) transpositioning idiom:

>>> lists = [[1, 2, 3], [ 4, 7, 8], [13, 9, 10]]
>>> lst = [2,6,9]
>>> list(map(takeClosest, lst, zip(*lists)))
# OR:  list(map(takeClosest, Mynumber, zip(Mylist1, Mylist2, Mylist3)))
[1, 7, 8]  # 9 is as close to 8 as it is to 10

This will apply your takeClosest function to (2, [1, 4, 13]), (6, [2, 7, 9]), etc.

Upvotes: 1

Dave Rosenman
Dave Rosenman

Reputation: 1467

Here's a kind of ugly way to do it.

Mylist1= [ 1, 2, 3]
Mylist2= [ 4, 7, 8]
Mylist3= [ 13, 9, 10]
Mynumber=[2,6,9]
closest_values = []
for num in range(len(Mynumber)):
    differences = {Mylist1[num]: abs(Mylist1[num]-Mynumber[num]), 
                   Mylist2[num]: abs(Mylist2[num]-Mynumber[num]),
                   Mylist3[num] : abs(Mylist3[num]-Mynumber[num])}
    closest_values.append(min(differences, key=differences.get))
print(closest_values)
#[1, 7, 8]

Upvotes: 0

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