CODEWITHSUNDEEP
javascript
user8227859
user8227859

Reputation: 65

Javascript Array ES6 Undefined Error

I'm having trouble solving this question (the result is always undefined) and I am not sure what I'm doing wrong... any ideas?

Write a function that takes a number and generates a list from 0 to that number.

Use the function to assign a value to the myNumberList variable so that it has the value of a list going from 0 to 5.

Assign a value to the variable secondLastItem that should be the second last item of the myNumberList array.

function listMaker(listLength) {}

var myNumberList = null; // replace with number list created by listmaker

var secondLastItem = null; // replace with second last item

Upvotes: 1

Views: 81

Answers (2)

Dream_Cap
Dream_Cap

Reputation: 2302

Here is one way to write it: 

     function listMaker(number) {
       var secondToLast;
       var list = [];
       
        for (var i = 0; i <= number; i++){
        list.push(i);
        	}
         secondToLast = list[list.length - 2];
          
         return [list, secondToLast]
        }
        
        
        var list = listMaker(5)[0];
        var secondToLast = listMaker(5)[1] 

console.log(list + "\n" + secondToLast);

That is the snippet ^

Here is the jsfiddle

Upvotes: 0

Mamun
Mamun

Reputation: 68933

You can try the following way using ES6's spread operator (...):

function listMaker(listLength) { 
   return [...Array(listLength).keys()];
} 
var myNumberList = listMaker(10);
// If you want the specified number passed as argument to be included as the last item in the array then push it.
myNumberList.push(10);
console.log(myNumberList);

Upvotes: 2

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