Reputation: 158
I'm building a "hovering" menu, using semantic-ui-react's Popup, and want to add a simple show-hide transition, how it can be done?
Upvotes: 3
Views: 2919
Reputation: 86
this is probably coming in too late for this specific OP, but might be useful for someone else trying to figure same out.
I believe you can use the TransionablePortal as shown in the example. Just for fun, I adapted that example to what I think you are trying to do:
import React, { Component } from 'react'
import { Button, Menu, TransitionablePortal } from 'semantic-ui-react'
export default class TransitionablePortalExamplePortal extends Component {
state = { open: false }
handleOpen = () => this.setState({ open: true })
handleClose = () => this.setState({ open: false })
render() {
const { open } = this.state
return (
<TransitionablePortal
closeOnTriggerClick
onOpen={this.handleOpen}
onClose={this.handleClose}
transition={{animation: "fade left", duration: 500 }}
openOnTriggerClick
trigger={
<Button circular basic
icon="ellipsis vertical"
negative={open}
positive={!open}
/>
}
>
<Menu vertical style={{ right: '1%', position: 'fixed', top: '0%', zIndex: 1000}}>
<Menu.Item>Menu Item 1</Menu.Item>
<Menu.Item>Menu Item 2</Menu.Item>
</Menu>
</TransitionablePortal>
)}}
You should be able to make the transition use onMouseEnter and onMouseLeave if you want same transition to be on hover, instead of on click.
Upvotes: 3
Reputation: 4394
You can find in their official documentation example where you can make custom style for popup
import React from 'react'
import { Button, Popup } from 'semantic-ui-react'
const style = {
borderRadius: 0,
opacity: 0.7,
padding: '2em',
}
const PopupExampleStyle = () => (
<Popup
trigger={<Button icon='eye' />}
content='Popup with a custom style prop'
style={style}
inverted
/>
)
export default PopupExampleStyle
You can try to add transition property here
Upvotes: 0