CODEWITHSUNDEEP
pythonhtmlpython-3.xreturnreturn-value
Kuunnn
Kuunnn

Reputation: 19

return HTML output to python

I'm building a local website in python to press a button, so the door to my room will open from my phone by using a raspberry pi. I already have made a python program, which, if ran, will open the door flawlessly, however, I am trying to make a button in HTML that will return something to execute the file which will open the door.

This is what I already have:

from flask import Flask, render_template
from test import open_door

app = Flask(__name__)


@app.route('/open/door')
def doorOpen():
    return render_template('door.html')

@app.route('/opendoor')
def openDoor():
    open_door()
    return 'the door should be open'


if __name__ == '__main__':
app.run(debug=True, host='0.0.0.0')

Here is test.py the file which will open the door if executed, and door.html is the following:

<html>
<body>
<a href="/opendoor" class="openbutton">Open for me please</a>
</body>
</html>

It is not something fancy but it only has to work for now. It looks to me like the return is not doing anything since i also added a return and a print function in the openDoor() function withouth any response. I couln't find any awnsers on the internet so i am curious what the problem is!

p.s. This is my first time with python and i am a beginner with HTML edit: this is test.py:

import RPi.GPIO as GPIO
import time

testPin = 18

GPIO.setmode(GPIO.BCM)
GPIO.setup(testPin, GPIO.OUT)

counter =0

def open_door():
    try:
        while counter < 900000:
            GPIO.output(testPin, GPIO.HIGH)

            counter += 1

    except:
        print ("Everything is oke!")

    finally:
        GPIO.cleanup()

Upvotes: 1

Views: 14303

Answers (1)

Ajax1234
Ajax1234

Reputation: 71471

Instead of an onclick function, you can route the button to another page on your localhost:

from flask import Flask, render_template
from test import open_door
app = Flask(__name__)

@app.route('/')
def doorOpen()
   return render_template('door.html')

@app.route('/opendoor')
def openDoor():
   open_door()

if __name__ == '__main__':
    app.run(debug=True, host='0.0.0.0')

In door.html:

<html>
<body>
<a href="/opendoor" class="openbutton">Open Door</a>
</body>
</html>

In the HTML file, class="openbutton" is for pure styling purposes.

Upvotes: 2

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