CODEWITHSUNDEEP
python
marsx
marsx

Reputation: 715

python: Searching strings in one list in another list, then appending an entire list entry to a new list

Example:

L1=['cat', 'dog', 'fish', 'bird', 'rabbit', 'horse']

L2=[('cat', 'a', 'b', 'c'), ('cat', 'c', 'd', 'e'), ('cat', 'e', 'f', 'g'), ('fish', 'x', 'y', 'z'), ('dog', 'w', 'x', 'y'), ('dog', 'z', 'y', 'x'), ('horse', '1', '2', '3'), ('monkey', 'a', 'b', 'c'), ('kitten', 'h', 'i', 'j'), ('bird', '4', '5', '6')]

I am trying to search the strings in L1 in L2, so that if the string in L1 is present in any part of L2, the whole entry from L2 "('cat, a, b, c')" is appended to a new list. I also thought that maybe removing the entries that do not have any part of a string from L1 would work. I tried:

def searcher(L1, L2):
    common = []
    for x in L1:
        if re.search(x, L2):
            common.append(L2)

    return common

but that didnt work. The actual list I am using is much longer, so an efficient code would really help me out.

Thanks!

Upvotes: 1

Views: 577

Answers (2)

Sven Marnach
Sven Marnach

Reputation: 601879

Try

s = set(L1)
new_list = [a for a in L2 if any(b in s for b in a)]

Upvotes: 5

Qnan
Qnan

Reputation: 3744

Maybe

s = set(L1)
new_list = [a for a in L2 if s.intersection([w.strip() for w in set(a.split(","))])]

Upvotes: 0

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