CODEWITHSUNDEEP
pythonpython-3.x
Yash
Yash

Reputation: 2033

In one of my operation on updating list in Python, I am getting unexpected result? Explain Please

I was trying to update the list in other scenario other than using map function. I tried loop and on one of my operation, I get unexpected result. Here is my code.

    #my_function_which_is_only_for_printing
    def app(l):
        for i in l:
            print(i)

    l=[1,2,'3','4'] #list_with_int_and_str
    app(l) #calling_function

    #As result my all output are integer
    #It Should be integer and character rather then all as integer

My Expected output is like this 1 2 3 4 And I should get it like this 1 2 '3' '4'

Upvotes: 0

Views: 45

Answers (1)

neehari
neehari

Reputation: 2612

Your function is doing what you want: 1 and 2 are of int type and '3' and '4' are of str type:

def app(l):
    for i in l:        
        print("{} is: {}".format(i, type(i)))

l = [1,2,'3','4']

app(l)

1 is: <class 'int'>
2 is: <class 'int'>
3 is: <class 'str'>
4 is: <class 'str'>

Edit: To get string representation of the list elements, like @Paul Panzer suggested in the comments, you could do print(repr(i)):

def app(l):
    for i in l:        
        print(repr(i), end=' ') # Print on the same line

l = [1,2,'3','4']

app(l)

1 2 '3' '4' 
>>>

repr(object) says:

Return a string containing a printable representation of an object.

Upvotes: 1

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