Reputation: 892
I have a list of objects A (alist
).
A {
val b : Int
val c1 : Int
val c2 : Int
val d1 : Int
val d2 : Int
}
and I want to group them by b
and calculate sum of c1+c2
and d1+d2
on each group and put the results in list of E objects elist
.
E {
val sum_of_c_types : Int
val sum_of_d_types : Int
}
How do I achieve in kotlin using any collection inbuilt function?
note:
I know I can do it with reduce
function and create temporary A objects, but this is important to dont use temporary A object in code.
Upvotes: 5
Views: 13332
Reputation: 81869
I've solved it by using a sequence of groupBy
, map
and sumBy
. It's probably not the cleanest solution I guess.
data class A(val b: Int,
val c1: Int,
val c2: Int,
val d1: Int,
val d2: Int)
data class E(val sumC: Int, val sumD: Int)
fun main(args: Array<String>) {
val alist = listOf(A(1, 2, 1, 4, 5), A(1, 3, 4, 6, 3), A(2, 2, 2, 2, 2), A(3, 1, 2, 1, 2))
val grouped: Map<Int, E> = alist.groupBy(A::b).mapValues {
E(it.value.sumBy { it.c1 + it.c2 }, it.value.sumBy { it.d1 + it.d2 })
}
grouped.forEach {
println("Group b=${it.key}: ${it.value}")
}
}
Results in:
Group b=1: E(sumC=10, sumD=18)
Group b=2: E(sumC=4, sumD=4)
Group b=3: E(sumC=3, sumD=3)
Edit:
With Grouping
(using groupingBy
instead of groupBy
), it looks even better because you don't have to handle map entities:
val grouped = alist.groupingBy(A::b).aggregate { _, acc: E?, e, _ ->
E((acc?.sumC ?: 0) + e.c1 + e.c2, (acc?.sumD ?: 0) + e.d1 + e.d2)
}
Upvotes: 8
Reputation: 17774
I think it's just grouping with folding
fun group(a: List<A>) = a.groupingBy(A::b).fold(E(0, 0),
{ acc, elem ->
E(acc.sum_of_c_types + elem.c1 + elem.c2,
acc.sum_of_d_types + elem.d1 + elem.d2)
})
Upvotes: 5
Reputation: 892
I solved it by following code:
alist.groupby { b }. mapValues {
it.value.map {
E(it.c1+it.c2, it.d1+it.d2)
}.reduce {
acc, e -> E(acc.sum_of_c_types + e.sum_of_c_types, acc.sum_of_d_types + e.sum_of_d_types)
}.values
Upvotes: 1