CODEWITHSUNDEEP
javaandroidhtml
Kingyal
Kingyal

Reputation: 63

Splitting characters

My characters is "!,;,%,@,**,**,(,)" which get from XML. when I split it with ',', I lost the ','.

How can I do to avoid it. I have already tried to change the comma to '&#002C', but it does not work.

Thre result I want is "!,;,%,@,,,(,)", but not "!,;,%,@,,(,)"

Upvotes: 0

Views: 89

Answers (4)

MC Emperor
MC Emperor

Reputation: 23047

First, we need to define when the comma is an actual delimiter, and when it is part of a character sequence.

We need to assume that a sequence of commas surrounded by commas is an actual character sequence we want to capture. It can be done with lookarounds:

String s = "!,;,,,%,@,**,**,,,,(,)";
List<String> list = Arrays.asList(s.split(",(?!,)|(?<!,),"));

This regular expression splits by a comma that is either preceded by something that is not a comma, or followed by something that is not a comma.

Note that your formatting string, that is, every character sequence separated by a comma, is a bad design, since you require both the possibility to use a comma as sequence, and the possibility to use multiple characters to be used. That means you can combine them too!

What, for example, if I want to use these two character sequences:

  • ,
  • ,,,,

Then I construct the formatting string like this: ,,,,,,. It is now unclear whether , and ,,,, should be character sequences, or ,, and ,,,.

Upvotes: 0

Youcef LAIDANI
Youcef LAIDANI

Reputation: 60046

String::split use regex so you can split with this regex ((?<!,),|,(?!,)) like this :

String string = "!,;,%,@,,,(,)";
String[] split = string.split("((?<!,),|,(?!,))");

Details

  • (?<!,), match a comma if not preceded by a comma
  • | or
  • ,(?!,) match a comma if not followed by a comma

Outputs

!
;
%
@
,
(
)

Upvotes: 2

janith1024
janith1024

Reputation: 1042

try this, this could be help full. First I replaced the ',' with other string and do split. After complete other string replace with ','

  public static void main(String[] args) {
    String str = "!,;,%,@,**,**,(,)";
    System.out.println(str);
    str = str.replace("**,**","**/!/**");
    String[] array = str.split(",");
    System.out.println(Arrays.stream(array).map(s -> s.replace("**/!/**", ",")).collect(Collectors.toList()));
  }

out put 

 !,;,%,@,**,**,(,)
 [!, ;, %, @, ,, (, )]

Upvotes: 0

Arjunlal
Arjunlal

Reputation: 154

If you are trying to extract all characters from string, you can do so by using String.toCharArray()[1] : 

String str = "sample string here";
char[] char_array = s.toCharArray();

If you just want to iterate over the characters in the string, you can use the character array obtained from above method or do so by using a for loop and str.charAt(i)[2] to access the character at position i.

[1] https://docs.oracle.com/javase/7/docs/api/java/lang/String.html#toCharArray() [2]https://docs.oracle.com/javase/7/docs/api/java/lang/String.html#charAt(int)

Upvotes: 0

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