CODEWITHSUNDEEP
pythondjango
heybro
heybro

Reputation: 11

django url.py error page not found

I can't make url.py. It still shows page not found.

These are my urls:

/pins/tag/?search=A/
/pins/tag/?search=B/
/pins/tag/?search=C/

A,B,C are variable strings.

This is my urls.py: 

url(r'^pins/tag/?search=(?P<tag>(\w|-)+)/$')

How do I make a correct urls.py?

Upvotes: 0

Views: 196

Answers (2)

Vipin Mohan
Vipin Mohan

Reputation: 1631

Regex like this would match anything except newline character (.*). So your URL should look something like this. If you just want Uppercase alphabets stick to [A-Z]

url(r'^pins/tag/?search=(?P<tag>.+)/$', views.search_tag , name='search_tag'),

views.py

def search_tag(request, tag):
    #do whatever here with tag

Upvotes: 1

Austine Owoh
Austine Owoh

Reputation: 1

I mapping the url like this in my projects

url(r'^pins/tags/(?P[\w.@+-]+)/$', 'what_app_search', name='search')

Give me a feel back if it resolve the mapping.

Upvotes: 0

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