CODEWITHSUNDEEP
javaandroidbitmapoverwrite
Dithesh
Dithesh

Reputation: 9

Image not overwriting on same name

I'm developing image editor app.. so each time the user have to save the image. So first i inserted

  String savedImageURL = MediaStore.Images.Media.insertImage(
                        getContentResolver(),
                        bitmap,
                        "Bird",
                        "Image of bird"
                );

this code, but it creating new file instead of overwriting.

So i use another method

public String saveImage(String folderName, String imageName) {
 String selectedOutputPath = "";
      if (isSDCARDMounted()) {
          File mediaStorageDir = new File(
                  Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_PICTURES), folderName);
          // Create a storage directory if it does not exist
          if (!mediaStorageDir.exists()) {
              if (!mediaStorageDir.mkdirs()) {
                  Log.d("PhotoEditorSDK", "Failed to create directory");
              }
          }
          // Create a media file name
          selectedOutputPath = mediaStorageDir.getPath() + File.separator + imageName;
          Log.d("PhotoEditorSDK", "selected camera path " + selectedOutputPath);
     File file = new File(selectedOutputPath);
     try {
                    FileOutputStream out = new FileOutputStream(file,true);
                    if (parentView != null) {
                        parentView.setDrawingCacheEnabled(true);
                        parentView.getDrawingCache().compress(Bitmap.CompressFormat.JPEG, 80, out);
                    }
                    out.flush();
                    out.close();
                } catch (Exception e) {
                    e.printStackTrace();
                }
     }
     return selectedOutputPath;
       }

But it also didn't work.

Does anyone know about overwrite a bitmap in the same name?

Upvotes: 1

Views: 2008

Answers (2)

Sardorbek Muhammadjonov
Sardorbek Muhammadjonov

Reputation: 181

I also had this situation, but it turns out that this is not a problem with saving, but with displaying in ImageViev. I used Glide, and it turns out to be stored in the cache when outputting. And I did not change the name and path of the file. That is, I rewrote them. But Glide did not know this. He thought they were the same file. To fix this problem, I added the following

Glide.with(context)
     .load(file)
     .diskCacheStrategy(DiskCacheStrategy.NONE)
     .skipMemoryCache(true)
     .into(view)

If you also have this situation and these solutions helped you, I'm glad to this.

Upvotes: 1

Vikas Suryawanshi
Vikas Suryawanshi

Reputation: 522

Pass false as 2nd argument, to set append to false, so that you will overwrite the existing file:

 FileOutputStream out = new FileOutputStream(file,false);

Check out the constructor documentation:

here is your code:

public String saveImage(String folderName, String imageName) {
 String selectedOutputPath = "";
    if (isSDCARDMounted()) {
        File mediaStorageDir = new File(Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_PICTURES), folderName);
      // Create a storage directory if it does not exist
      if (!mediaStorageDir.exists()) {
          if (!mediaStorageDir.mkdirs()) {
              Log.d("PhotoEditorSDK", "Failed to create directory");
          }
      }
      // Create a media file name
      selectedOutputPath = mediaStorageDir.getPath() + File.separator + imageName;
      Log.d("PhotoEditorSDK", "selected camera path " + selectedOutputPath);
 File file = new File(selectedOutputPath);

if (file.exists()) 
{
  try {
            file.delete();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }


 try {
 file.createNewFile();
                FileOutputStream out = new FileOutputStream(file,false);
                if (parentView != null) {
                    parentView.setDrawingCacheEnabled(true);
                    parentView.getDrawingCache().compress(Bitmap.CompressFormat.JPEG, 80, out);
                }
                out.flush();
                out.close();
            } catch (Exception e) {
                e.printStackTrace();
            }
 }
 return selectedOutputPath;
   }

Upvotes: 1

Related Questions