CODEWITHSUNDEEP
pythongoogle-cloud-platformstringio
Tomislav Mikulin
Tomislav Mikulin

Reputation: 5936

google storage python API - uploading an StringIO object

I succeeded in uplaoding a file to the google storage, but I would like to skip the creation of a file and use StringIO instead and create the file on the google storage directly.

Since I'm new to python, I just tried to use the standard method that I used for uploading the created file:

def cloud_upload(self, buffer, bucket, filename):
    buffer.seek(0)
    client = storage.Client()
    bucket = client.get_bucket(bucket)
    blob = bucket.blob(filename)
    blob.upload_from_filename(buffer)

But I get the error:

TypeError: expected string or buffer

But since I gave it the StringIO object, I don't know why this isn't working?

Upvotes: 4

Views: 3183

Answers (3)

SirJ
SirJ

Reputation: 183

Cause you are uploading from filename. But should upload from file object rather. Should be:

blob.upload_from_file(buffer)

Upvotes: 0

deedeeck28
deedeeck28

Reputation: 367

Hope this is still relevant. But you can try using blob.upload_from_string method

def cloud_upload(self, buffer, bucket, filename):
    client = storage.Client()
    bucket = client.get_bucket(bucket)
    blob = bucket.blob(filename)
    blob.upload_from_string(buffer.getvalue(),content_type='text/csv')

Do take note to modify the content_type parameter if you want to save the file as other file types. I placed 'text/csv' as an example. The default value is 'text/plain'.

Upvotes: 8

patilnitin
patilnitin

Reputation: 1171

I am not sure how are you invoking the cloud_upload function but you can simply use the upload_from_filename function to satisfy your need.

def upload_blob(self, bucket_name, source_file_name, destination_blob_name):
    """Uploads a file to the bucket."""
    storage_client = storage.Client()
    bucket = storage_client.get_bucket(bucket_name)
    blob = bucket.blob(destination_blob_name)

    blob.upload_from_filename(source_file_name)

    print('File {} uploaded to {}.'.format(
        source_file_name,
        destination_blob_name))

Upvotes: -1

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