CODEWITHSUNDEEP
pythondjango
user8817894
user8817894

Reputation:

super function in Python

Wrt to the code snippet below, why is super().__init__ used in the model? How does it work?

model.py

class DuckForm(forms.ModelForm):
    class Meta:
        model = Duck
        fields = ('description', 'name')

    def __init__(self, community, *args, **kwargs):
        super().__init__(*args, **kwargs)
        self.community = community

    def save(self, commit=True):
        duck = super().save(commit=False)
        if not duck.community_id:
            duck.community = self.community

        if commit:
            duck.save()
        return duck

views.py

def add_duck(request):
    if request.method == 'POST':
        form = DuckForm(request.animal.community, data=request.POST)
        if form.is_valid():
            duck = form.save()
            return redirect('DuckData')
    else:
        form = DuckForm(request.user.community)
    return TemplateResponse(request, 'MyDuck.html', {'form': form})

Upvotes: 0

Views: 1045

Answers (1)

Aaron Klein
Aaron Klein

Reputation: 604

Calling super.method calls the method method of the parent class, in this case ModelForm. This is necessary in this case because Django models and forms have all sorts of strange things that happen to them in the __init__ method, and if you don't call super().__init__() those won't happen and the object won't behave as expected.

Also as a side note, this is invalid syntax in python 2 (but completely valid and correct in python 3). You would have to write super(DuckForm, self).__init__ to achieve the same goal.

Upvotes: 4

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